NEET Class neet Answered

Let the current distribution in the circuit is as shown in figure.

In the cloded loop ABEFGA , if we apply Kirchoff's voltage law , we get

...................(1)

In the cloded loop  BCDEB , if we apply Kirchoff's voltage law , we get

...................(2)

By solving eqn.(1) and (2) , we get

i₁ = 2 A  ;  i₂ = 2 A  ; 

By Kirchoff's current law applied to junction B, we get

By substituting i₁ and i₂ in above eqn. , we get i₃ = 0 A

Hence answer to the question :-

Ammeter A₁ shows 2 A and ammeter A₂ shows 0 A