CBSE Class 8 Answered
We know that,
the product of two numbers = product of their HCF and LCM
here, HCF × LCM = 9 × 819 = 7371.
Since the unit number is 1, the number cannot a multiple of 2 or 5.
The number must be an odd number and a multiple of 9.
So, 27 and 63 are the possibiliies of numbers.
If one number is 27 then the other number is 7371/27 = 273
Factors of 27 = 3 x 9 and factors of 273 = 3 x 91.
Here, the HCF is 3 and LCM = 3 x 9 x 91 = 2457.
So, this pair is not acceptable.
If one number is 63 then the other number is 7371/63 = 117.
Factors of 63 = 3 x 3 x 7 and 117 = 3 x 3 x 13
HCF = 3 x3 = 9
LCM - 3 x 3 x 7 x 13 = 819.
So, this pair is the answer.
Therefore, the required two numbers are 63 and 117.