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A solution of glucose in water is labelled as 10% (w/w). The density of the solution is 1.20 g/mL. Calculate molality, molarity and mole fraction of each component in solution A solution of glucose in water is labelled as 10% (w/w). The density of the solution is 1.20 g/mL. Calculate molality, molarity and mole fraction of each component in solution
Asked by tps.mjmdr | 29 May, 2018, 08:08: PM
answered-by-expert Expert Answer
10 space g m space g l u cos e space i s space p r e s e n t space i n space 100 space g space s o l u t i o n space therefore space 90 space g m space o f space w a t e r space equals space 0.090 space k g space o f space w a t e r 10 space g space o f space g l u cos e space equals space 10 over 180 space m o l e space equals space 0.0555 space m o l 90 space g space H subscript 2 O space equals space 90 over 18 equals space 5 space m o l e s M o l a r i t y space equals space fraction numerator 0.0555 over denominator 0.090 end fraction space equals space 0.617 space M N o w space l e t apostrophe s space f i n d space m o l e space f r a c t i o n space o f space g l u cos e comma M o l e space f r a c t i o n space o f space space g l u cos e space equals space fraction numerator 0.0555 over denominator 5 space plus space 0.0555 end fraction space equals space 0.01 N o w comma space M o l e space f r a c t i o n space o f space w a t e r space equals space 1 space minus space 0.01 space equals space 0.99 T h e space d e n s i t y space o f space g i v e n space s o l u t i o n space i s space 1.2 space g divided by m l comma space t h e n space t h e space v o l u m e space o f space t h e space 100 space g space s o l u t i o n space c a n space b e space g i v e n space a s space 100 g space o f space s o l u t i o n space equals fraction numerator 100 over denominator 1.2 end fraction space equals space 83.33 m l space equals space 83.33 space cross times space 10 to the power of negative 3 end exponent space L therefore space M o l a r i t y space o f space t h e space s o l u t i o n space equals space fraction numerator 0.0555 space m o l over denominator 83.33 space cross times space 10 to the power of negative 3 end exponent space L end fraction space equals space 0.67 space M
Answered by Ramandeep | 30 May, 2018, 10:15: AM

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