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CBSE Class 11-science Answered

A person walks 25.0o north of east for 3.18 Km. How far would she have to walk due north and then due east to arrive at the same location?
a. towards north 2.88 Km and towards east 1.34 km
b. towards north 2.11 km and towards east 2.11 km 
c. towards north 1.25 km and towards east 1.93 km
d. towards north 1.34 km and towards east 2.88 km
Asked by Anil | 22 Aug, 2017, 09:45: PM
answered-by-expert Expert Answer
Basically, this question is asking you to find the components of a vector 25.0° North of East with a magnitude of 3.10 km. 
 
 
y = R sin25° = 3.10 × sin25° = 1.31 km
x = R cos25° = 3.10 × cos25° = 2.81 km
Thus the correct option is (a)
Answered by Yashvanti Jain | 23 Aug, 2017, 09:22: AM

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