Two forces of 5 kg and 12 kg are connected at the two end of the light inextensible string that passes over a frictionless pulley. Find the acceleration of the masses and the tension in the string, when the masses are released.

Asked by Topperlearning User | 5th Jun, 2014, 04:04: PM

Expert Answer:

M1 = 5 kg, M2 = 12 kg

For the mass M1, we have
M1a = T - M1g

For the mass M2, we have
M2a = M2g - T

Adding the above equations, we get
(M1 + M2) a = (M2 - M1) g

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Hence, the tension in the string is
T = M1a + M1g
  = 5×4.04 + 5×9.8 = 69.2 N

Answered by  | 5th Jun, 2014, 06:04: PM