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CBSE Class 12-science Answered

A long straight conductor carrying current of 5A is placed in north south direction. Find the magnetic field due to 15 cm piece of the conductor at a point 3m-north east from the piece, if the current is flowing from south to north.
Asked by Topperlearning User | 18 May, 2015, 03:52: PM
answered-by-expert Expert Answer

I = 5A, dl = 15 cm = 0.15 m, r = 3 m, θ = 45°

According to Biot Savart’s law,

 begin mathsize 11px style dB space equals space fraction numerator straight mu subscript 0 over denominator 4 straight pi end fraction fraction numerator Idl space sinθ over denominator straight r squared end fraction space equals space fraction numerator 10 to the power of negative 7 end exponent space cross times space 5 space cross times space 0.15 space cross times space sin 45 to the power of degree over denominator 9 end fraction space equals space 5.8 space cross times space 10 to the power of negative 19 end exponent straight T end style

Answered by | 18 May, 2015, 05:52: PM
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