Contact

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

# A CAR TRAVELLS 6KM TOWARDS NORTH AN ANGLE OF 45 DEGREES TO THE EAST AND THEN TRAVELS DISTANCE OF 4 KM TOWARDS NORTH AT AN ANGLE OF 135 DEGREES TO THE EAST.HOW FAR IS THE POINT FROM THE STARTING POINT.WHAT ANGLE DOES THE STRAIGHT LINE JOINING IS INITIAL AND FINAL POSITION MAKES WITH THE EAST

Asked by pulagalarao.137 5th July 2019, 6:06 PM
Let the car starts from O, origin of X-Y coordinate system.
It travels 6 km along the direction OA which is towards north and the line of travel makes 45° to East.
Then the car travels 4 km along AB towards north at an angle of 135° to East.

As shown in figure, coordinate of final position of the car ( √2 km, 5√2 km ).

Hence the displacement OB =
BOA = tan-1(4/6) ≈ 34° . Initially OA makes an angle 45° to X-axis .
Hence OB makes an angle 79° to X-axis (East) .
Answered by Expert 6th July 2019, 10:15 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer 3/10

Tags: displacement