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  A capacitor of capacitance C1 = 1μF, charged up to a voltage V = 110V is connected in parallel to the terminals of a circuit consisting of two uncharged capacitors connected in series and possessing capacitance C2 = 2μF and C3 = 3μF. Then the amount of charge that will flow through the connecting wire :-
Asked by Prashant DIGHE | 13 Apr, 2020, 10:12: PM
answered-by-expert Expert Answer
 
L e t space q space b e space t h e space c h a r g e space f l o w i n g space t h r o u g h space w i r e s. W e space k n o w comma space minus increment phi space equals 0 equals fraction numerator C 1 V 1 space minus space q over denominator C 1 end fraction plus fraction numerator q over denominator C 2 end fraction plus fraction numerator q over denominator C 3 end fraction equals 0 q space equals space fraction numerator V over denominator begin display style fraction numerator 1 over denominator C 1 end fraction end style plus begin display style fraction numerator 1 over denominator C 2 end fraction end style plus begin display style fraction numerator 1 over denominator C 3 end fraction end style end fraction space equals space fraction numerator 110 over denominator begin display style 1 over 1 end style plus begin display style 1 half end style plus begin display style 1 third end style end fraction space equals space 60 mu C
Answered by Shiwani Sawant | 13 Apr, 2020, 10:52: PM
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  A capacitor of capacitance C1 = 1μF, charged up to a voltage V = 110V is connected in parallel to the terminals of a circuit consisting of two uncharged capacitors connected in series and possessing capacitance C2 = 2μF and C3 = 3μF. Then the amount of charge that will flow through the connecting wire :-
Asked by Prashant DIGHE | 13 Apr, 2020, 10:12: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
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