NEET Class neet Answered
clear my doubt.
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Asked by rahmansufia395 | 29 Jun, 2021, 08:42: AM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/6d289731b98c9f0996c1a84a09748e0260dac61e161061.93335741f1.png)
Let us assume the charge on each capacitor as shown in figure .
Potential difference between P and Q is given as
![begin mathsize 14px style q subscript 2 over C space plus space q subscript 3 over C space plus space q subscript 4 over C space equals space V subscript o end style](https://images.topperlearning.com/topper/tinymce/cache/fe0e1a57ee85521a279f177626894cdc.png)
Hence we get , q2 + q3 + q4 = C Vo ................................. (1)
Similarly , considering same potential difference between Q and R is applied to capacitors , we get ,
q3 + q4 = q5 ............................ (2)
From (1) and (2) , we have , q2 + q5 = C Vo ...............................(3)
By charge conservation , at node point Q , we have
q2 = q3 + q5 ..........................(4)
Above expression is written as , q2 - q5 = q3 ............................(5)
By solving equations (3) and (5) , we get ,
q2 = (1/2) [ q3 + C Vo ] ............................... (6)
q5 = (1/2) [ C Vo - q3 ] ................................(7)
At node point '2' , by charge conservation , q3 = q4 ......................(8)
From eqn.(2) and eqn.(8) , we get q5 = 2 q3 .................(9)
From eqn.(7) and (9) , we get , q3 = (1/5) C Vo ......................(10)
Potential difference between points '1' and '2' = ( q3 / C ) = (1/5) Vo
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