NEET Class neet Answered
physics
![question image](http://images.topperlearning.com/topper/new-ate/top_mob16961454091026438270538c87c7-7695-4b00-a9cd-a25af511b2fa.jpg)
Asked by ronit20a1 | 01 Oct, 2023, 13:00: PM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/fa7b1d765e9d361028d4fcb9adcb538d65194d52d0c3a6.60692159f4.png)
Each capacitor is connected individually to battery of EMF V through a resistance R and is getting charged.
At steady state , potential difference across each capacitor is V .
Hence total energy E stored is
![begin mathsize 14px style E space equals space 1 half left parenthesis space 4 C space right parenthesis space V to the power of 2 to the power of space end exponent space plus space space 1 half left parenthesis space 3 C space right parenthesis space V to the power of 2 to the power of space end exponent plus space 1 half left parenthesis space 2 C space right parenthesis space V to the power of 2 to the power of space end exponent plus space space 1 half left parenthesis space C space right parenthesis space V to the power of 2 to the power of space end exponent end style](https://images.topperlearning.com/topper/tinymce/cache/c0b026c506338cbde52d56ba0e060881.png)
![begin mathsize 14px style E space equals space 5 space C space V squared end style](https://images.topperlearning.com/topper/tinymce/cache/63a5f93f8099d3f813025a1f02cd00dd.png)
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