CBSE Class 12-science Answered
A 10% solution of urea ( molar mass 60) is found to be isotonic with a 5% solution of an unknown non-electrolyte substance.The molecular mass of unknown substance is
(a) 40%
(b) 50%
(c) 45%
(d) 30%
Asked by kaushikmisty07 | 31 Dec, 2023, 11:42: AM
Expert Answer
Dear Student,
We know that, osmotic pressure is represented by,
Π = CRT
Isotonic so, Π of urea solution = Π of x solution
C1RT = C2RT
C1 = C2
1 dm3 = 1L
C of urea = 10 g / 60 g ( mol wt of urea = 60 g)
C of x = (5 × 1000) / (mol. wt of x × 100)
10 / 60 = (5 × 1000) / (mol. wt of x × 100)
Solving,
Mol. wt of x = 300 g
Answered by | 31 Dec, 2023, 04:20: PM
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