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Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

N2 (g)   + 3H2 (g)   → 2NH3 (g)

1 vol.     3vol.        2vol.

N2: NH3                      N2: H2    

1:2                         1:3

Let the volume of ammonia produced and the volume of consumed hydrogen be x litres and y litres respectively.

200:x                  200:y

x=2 ×200           y = 200 ×3

x= 400              y=600

Hence, volume of ammonia produced =400 litres and the volume of excess hydrogen =1000 -600=400 litres                     


Answered by Expert 4th June 2014, 3:23 PM
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