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i f space space open vertical bar x plus bevelled 1 over x close vertical bar to the power of 2 space end exponent space equals space 3 space space. f i n d space x cubed space plus space bevelled 1 over x to the power of 3. end exponent

Asked by chitranshranjan178 7th December 2015, 6:42 PM
Answered by Expert
Answer:

 

begin mathsize 11px style open parentheses straight x plus 1 over straight x close parentheses squared equals straight x squared plus 1 over straight x squared plus 2 open parentheses straight x close parentheses open parentheses 1 over straight x close parentheses equals straight x squared plus 1 over straight x squared plus 2 space rightwards double arrow 3 equals straight x squared plus 1 over straight x squared plus 2 rightwards double arrow straight x squared plus 1 over straight x squared equals 1 straight x cubed plus 1 over straight x cubed equals open parentheses straight x plus 1 over straight x close parentheses open parentheses straight x squared minus 1 plus 1 over straight x squared close parentheses equals open parentheses plus-or-minus 3 close parentheses open parentheses 1 minus 1 close parentheses equals 0 end style

Answered by Expert 7th December 2015, 6:52 PM
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