CBSE Class 10 Maths Converse of BPT
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Converse of BP theorem
Statement and derivation of the converse of the Basic Proportionality Theor -
Statement and derivation of the converse of the Basic P
Statement and derivation of the converse of the Basic Proportionality Theor -
More on converse of BP theorem
Statement and derivation of the converse of the Basic Proportionality Theor
- In quadrilateral ABCD; P,Q,R and S are points of trisection of sides AB, BC, CA and AD. Prove PQRS is a Parallelogram. In the solution of this question shown in the video(exam decoded of converse of BPT section), its shown that : BP = 2AP, BQ = 2QC, DR = 2RC and DS = 2SA. explain this step in detail that how is this possible
- converse of bpt
- State the converse of Pythagoras theorem
- Converse of Thales theorm
- Converse pythagoras therom
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given a triangle ABC and a trapezium BCED
AD=1,AB=3,AE=2,AC=x,EC=?
- In a trapezium ABCD, E and F are points on AB and AD respectively. Also G and H are points on CB and CD respectively such that AE=3, AB=9, AF=2, AD=6, CG=1, CB=4, CH=3, CD=4. Check if EF || GH.
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