CBSE Class 10 - Converse of BPT Videos
Statement and derivation of the converse of the Basic Proportionality Theorem
Statement and derivation of the converse of the Basic Proportionality Theorem and solve problems based on them.
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Derivation of BP theorem
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Statement and derivation of the converse of the Basi ...
- In quadrilateral ABCD; P,Q,R and S are points of trisection of sides AB, BC, CA and AD. Prove PQRS is a Parallelogram. In the solution of this question shown in the video(exam decoded of converse of BPT section), its shown that : BP = 2AP, BQ = 2QC, DR = 2RC and DS = 2SA. explain this step in detail that how is this possible
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given a triangle ABC and a trapezium BCED
AD=1,AB=3,AE=2,AC=x,EC=?
- In a trapezium ABCD, E and F are points on AB and AD respectively. Also G and H are points on CB and CD respectively such that AE=3, AB=9, AF=2, AD=6, CG=1, CB=4, CH=3, CD=4. Check if EF || GH.
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