ICSE Class 10 Answered
(x-3) is a factor of x to the power 3 + ax to the power 2+ bx - 9 and when it is divided by (x - 2) the remainder is 1
Asked by kushalsahu20march | 16 May, 2019, 11:56: AM
Expert Answer
Let p(x) =x3 + ax2 + bx - 9
(x-3) is a factor of x3 + ax2 + bx - 9 .. given
→ p(3) = 0
→ (3)3 + a(3)2 + b(3) - 9 = 0
→ 27 + 9a + 3b - 9 = 0
→ 3a + b = -6 ... (i)
when p(x) is divided by (x - 2) the remainder is 1 ... given
→ p(2) = 1
→ (2)3 + a(2)2 + b(2) - 9 = 1
→ 4a + 2b = 2
→ 2a + b = 1 .... (ii)
Solving (i) and (ii), we get
a = -7 and b = 14
Answered by Yasmeen Khan | 16 May, 2019, 12:25: PM
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