Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

x^2+6x-(a^2+2a-8)=0
question image
Asked by anjalisinghdps16 | 15 Sep, 2020, 23:49: PM
answered-by-expert Expert Answer
x2 + 6x - (a2 + 2a - 8) = 0
x2 + 6x - (a2 + 2a + 1 - 9) = 0
x2 + 6x - (a2 + 2a + 1) + 9 = 0
x2 + 6x + 9 - (a + 1)2 = 0
(x + 3)2 - (a + 1)2 = 0
[x + 3 - (a + 1)][(x+3)+(a+1)]=0
x - a + 4 = 0 OR x + a + 4 = 0
x - a = -4 ... (i)
x + a = -4 ... (ii)
Adding the two we get
2x = -8
x = -4
From (i), we get
-4 - a = -4
a = 0
Answered by Renu Varma | 18 Sep, 2020, 12:00: PM
CBSE 10 - Maths
Asked by gurjaeharsh |
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by humangisevda28 |
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by anjalisinghdps16 |
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by g.pavithran2002 |
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by labheshvaidya |
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by mayankgoransh0564 |
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by Topperlearning User |
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×