2x^2-7x+3=0 by method of completing square

Asked by g.pavithran2002 | 6th Jul, 2020, 04:35: PM

Expert Answer:

To solve 2x2 - 7x + 3 = 0 using completing square method
2x2 - 7x + 3 = 0
x2 - 7/2 x + 3/2 = 0
 
straight x squared minus 2 cross times 7 over 4 straight x plus 3 over 2 equals 0
straight x squared minus 2 cross times 7 over 4 straight x plus 49 over 16 minus 49 over 16 plus 3 over 2 equals 0
straight x squared minus 2 cross times 7 over 4 straight x plus open parentheses 7 over 4 close parentheses squared minus 49 over 16 plus 24 over 16 equals 0
open parentheses straight x minus 7 over 4 close parentheses squared plus fraction numerator 24 minus 49 over denominator 16 end fraction equals 0
open parentheses straight x minus 7 over 4 close parentheses squared plus fraction numerator negative 25 over denominator 16 end fraction equals 0
open parentheses straight x minus 7 over 4 close parentheses squared equals 25 over 16
straight x minus 7 over 4 equals plus-or-minus 5 over 4
straight x equals fraction numerator 7 plus-or-minus 5 over denominator 4 end fraction
straight x equals 3 space or space straight x equals 1 half

Answered by Renu Varma | 7th Jul, 2020, 11:29: AM