# CBSE Class 10 Answered

**Write the number of consecutive zeros in the prime factorization of a natural number N given by 2?×3?×5³×11.**

Asked by priyankakiran2017 | 18 May, 2022, 16:06: PM

Expert Answer

Number of zeroes = min(a, b)

Here a and b are the exponents of 2 and 5

THerefore, number of zeroes = min{4, 3} = 3

Answered by Renu Varma | 19 May, 2022, 16:05: PM

## Application Videos

## Concept Videos

CBSE 10 - Maths

Asked by anunithachrissy5 | 12 Aug, 2024, 20:21: PM

ANSWERED BY EXPERT

CBSE 10 - Maths

Asked by nsvramanaramana | 29 Jun, 2024, 19:18: PM

ANSWERED BY EXPERT

CBSE 10 - Maths

Asked by rashmij34 | 21 Mar, 2023, 17:01: PM

ANSWERED BY EXPERT

CBSE 10 - Maths

Asked by rimrimsangma36 | 12 Mar, 2023, 04:57: AM

ANSWERED BY EXPERT

CBSE 10 - Maths

Asked by ravindar.sanka123 | 07 Jul, 2022, 13:30: PM

ANSWERED BY EXPERT

CBSE 10 - Maths

Asked by priyankakiran2017 | 18 May, 2022, 16:06: PM

ANSWERED BY EXPERT

CBSE 10 - Maths

Asked by KANIMETImadhvi | 28 Mar, 2022, 06:53: AM

ANSWERED BY EXPERT

CBSE 10 - Maths

Asked by nikhilgurung763 | 30 Nov, 2021, 17:47: PM

ANSWERED BY EXPERT

CBSE 10 - Maths

Asked by rajeevkumargupta8 | 16 May, 2021, 17:32: PM

ANSWERED BY EXPERT