CBSE Class 10 Answered
Write the number of consecutive zeros in the prime factorization of a natural number N given by 2⁴×3⁴×5³×11.
Asked by priyankakiran2017 | 18 May, 2022, 04:06: PM
Expert Answer
Number of zeroes = min(a, b)
Here a and b are the exponents of 2 and 5
THerefore, number of zeroes = min{4, 3} = 3
Answered by Renu Varma | 19 May, 2022, 04:05: PM
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