when x molecules are removed from 200mg N2O(nitric oxide), 2.89/1/1000 moles of N2O are left. how much will be x?answer should be in grams. please describe.

Asked by OM mohapatra | 1st Aug, 2014, 10:36: AM

Expert Answer:

Molar mass of N2O = 44 g

Number of moles of N2O in 44 g = 1

Number of moles of N2O in 1g of N2O = 1 / 44

Number of moles of N2O in 200 mg or 200 × 10-3 g of N2O = 200 × 10-3 / 44 =  4.545 × 10-3 moles

 

Number of moles of N2O left = 2.89 × 10-3 moles……(Given)

Total Number of moles of N2O = 4.545 × 10-3 moles

Number of moles removed of N2O = 4.545 × 10-3 – 2.89 × 10-3 = 1.655 × 10-3 moles

 

1 mole of N2O = 6.022 × 1023 molecules of N2O

1.655 × 10-3 moles of N2O = 1.655 × 10-3 ×  6.022 × 1023 molecules of N2O  = 9.96 × 1020 molecules of N2O

Answered by Arvind Diwale | 8th Aug, 2014, 11:49: AM