what volume of 6M hcl and 2M hcl should be mixed to get 1 litre of 3M hcl?

Asked by ayushikas | 21st May, 2011, 09:14: PM

Expert Answer:

Suppose the volume of 6M HCl required to prepare 1 L of 3M HCl = x L
Volume of 2M HCl required = 1 - x L
Apply molarity equation
M1V1 + M2V2 = M3V3
6 × (x) + 2 ( 1-x) = 3 x 1
6x + 2 - 2x = 3
4x +2 = 3
4x = 3 - 2
4x = 1
x = 1/4 = 0.25 L
so volume of 6M HCl required = 0.25 L
   volume of 2M HCl required = 1 - 0.25 = 0.75 L

Answered by  | 21st May, 2011, 04:36: PM

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