CBSE Class 11-science Answered
<div>what mass of iron is liberated from a solution of potassium iodide when 1 litre of chlorine gas at 10 degree C and 750mm pressure is passed through it ?</div>
Asked by komal | 01 Jul, 2016, 07:04: AM
Expert Answer
Data:
P = 750 mm Hg
1 atm= 760 mm Hg
So 750 mm Hg = 0.9868 atm
V = 1 L
R = 0.082 L atm mol-1 K-1
T = 10°C =283 K
Solution:
We know PV = n RT
0.9868x 1 =n x 0.082 x283
n= 0.042 mol
1 mole of KI reacts with 1 mole of Cl2 to form 1 mole of I2.
So 0.042 mole of KI reacts with 0.042 mole of Cl2 to form 0.042 mole of I2.
Amount of I2 liberated = No. of moles x molar mass = 0.042 x 253.81 = 10.793 g
Answered by Vaibhav Chavan | 01 Jul, 2016, 12:21: PM
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