what mass of iron is liberated from a solution of potassium iodide  when 1 litre of chlorine gas at 10 degree C and 750mm pressure is passed through it ?

Data:

P = 750 mm Hg

1 atm= 760 mm Hg

So 750 mm Hg = 0.9868 atm

V = 1 L

R = 0.082 L atm mol^-1 K^-1

T = 10°C =283 K

Solution:

We know PV = n RT

0.9868x 1 =n x 0.082 x283

n= 0.042 mol

1 mole of KI reacts with 1 mole of Cl₂ to form 1 mole of I₂.

So 0.042 mole of KI reacts with 0.042 mole of Cl₂ to form 0.042 mole of I₂.

Amount of I₂ liberated = No. of moles x molar mass = 0.042 x 253.81 = 10.793 g