what mass of iron is liberated from a solution of potassium iodide  when 1 litre of chlorine gas at 10 degree C and 750mm pressure is passed through it ?

Asked by komal | 1st Jul, 2016, 07:04: AM

Expert Answer:

Data:

P = 750 mm Hg

1 atm= 760 mm Hg

So 750 mm Hg = 0.9868 atm

V = 1 L

R = 0.082 L atm mol-1 K-1

T = 10°C =283 K

Solution:

We know PV = n RT

0.9868x 1 =n x 0.082 x283

n= 0.042 mol

1 mole of KI reacts with 1 mole of Cl2 to form 1 mole of I2.

So 0.042 mole of KI reacts with 0.042 mole of Cl2 to form 0.042 mole of I2.

Amount of I2 liberated = No. of moles x molar mass = 0.042 x 253.81 = 10.793 g

Answered by Vaibhav Chavan | 1st Jul, 2016, 12:21: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.