What is the probability that both will visit the shop on: 1 the same day 2 different days 3 consecutive days
Asked by
| 23rd Feb, 2012,
06:57: PM
Since each person has 6 days to visit, so the total number combination of their visit is 6 × 6 = 36
Number of ways in which they visit on same day is 6 (MM, TT, WW, TT, FF, SS)
So, P(They visit on same day) = 6/36 = 1/6
P(They visit on different days) = 1 (1/6) = 5/6
For consecutive days we have (MT, TW, WT, TF, FS) × 2 = 10
P(They visit on consecutive days) = 10/36 = 5/18
Since each person has 6 days to visit, so the total number combination of their visit is 6 × 6 = 36
Number of ways in which they visit on same day is 6 (MM, TT, WW, TT, FF, SS)
So, P(They visit on same day) = 6/36 = 1/6
P(They visit on different days) = 1 (1/6) = 5/6
For consecutive days we have (MT, TW, WT, TF, FS) × 2 = 10
P(They visit on consecutive days) = 10/36 = 5/18
Answered by
| 24th Feb, 2012,
09:34: AM
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