CBSE Class 11-science Answered
What is the mass of carbon present in 0.5 mole of K4[Fe(CN)6]?
Asked by | 07 May, 2012, 12:07: AM
Expert Answer
Total molar mass of K4[Fe(CN)6] = 368 g/mol
Mass of 1 mol of K4[Fe(CN)6] = 368 g/mol
So, Mass of 0.5 mol of K4[Fe(CN)6] = 368 x 0.5 g/mol = 184 g/mol
Mass of C in K4[Fe(CN)6]= 6x 12=72 g/mol
Let mass of Carbon in this compound is A
Then,
A/184 = 72/368 = 36 g/mol
hence, mass of carbon in 0.5 mol is 36 g/mol
Answered by | 07 May, 2012, 08:53: AM
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