what is the % increase in the area of the triangle if each side is doubled?
Asked by shrsanchi | 17th Apr, 2008, 10:40: PM
Let the sides of the triangle be x,y,z
Using the Heron's formula Are of that triangle
= A =S(S-x)(S-y)(S-z) where S = (x+y+z)/2 , the semiperimeter.
The New triangle has sides 2x,2y,2z
So S' = (2x+2y+2z)/2 =x+y+z = 2S
A' = 2S(2S-2x)(2S-2y)(2S-2z) =4A
Incrtease in Area = 4S - S = 3S
Percentage Increase in Area = 3S/S * 100 = 300 percent
Answered by | 12th May, 2008, 12:02: PM
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