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CBSE Class 11-science Answered

What is the answer for this question?
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Asked by dineshchem108 | 16 Apr, 2019, 10:58: PM
answered-by-expert Expert Answer
begin mathsize 16px style limit as straight x rightwards arrow 0 of space fraction numerator square root of straight x squared plus 1 end root minus 1 over denominator square root of straight x squared plus 9 end root minus 3 end fraction equals limit as straight x rightwards arrow 0 of space fraction numerator square root of straight x squared plus 1 end root minus 1 over denominator square root of straight x squared plus 9 end root minus 3 end fraction cross times fraction numerator square root of straight x squared plus 9 end root plus 3 over denominator square root of straight x squared plus 9 end root plus 3 end fraction equals limit as straight x rightwards arrow 0 of space fraction numerator open parentheses square root of straight x squared plus 1 end root minus 1 close parentheses open parentheses square root of straight x squared plus 9 end root plus 3 close parentheses over denominator straight x squared plus 9 minus 9 end fraction equals limit as straight x rightwards arrow 0 of space fraction numerator open parentheses square root of straight x squared plus 1 end root minus 1 close parentheses open parentheses square root of straight x squared plus 9 end root plus 3 close parentheses over denominator straight x squared end fraction cross times fraction numerator square root of straight x squared plus 1 end root plus 1 over denominator square root of straight x squared plus 1 end root plus 1 end fraction equals limit as straight x rightwards arrow 0 of space fraction numerator open parentheses straight x squared plus 1 minus 1 close parentheses open parentheses square root of straight x squared plus 9 end root plus 3 close parentheses over denominator straight x squared open parentheses square root of straight x squared plus 1 end root plus 1 close parentheses end fraction equals equals limit as straight x rightwards arrow 0 of space fraction numerator straight x squared open parentheses square root of straight x squared plus 9 end root plus 3 close parentheses over denominator straight x squared open parentheses square root of straight x squared plus 1 end root plus 1 close parentheses end fraction equals limit as straight x rightwards arrow 0 of space fraction numerator square root of straight x squared plus 9 end root plus 3 over denominator square root of straight x squared plus 1 end root plus 1 end fraction equals fraction numerator 3 plus 3 over denominator 1 plus 1 end fraction equals 3 end style
Answered by Sneha shidid | 17 Apr, 2019, 09:13: AM

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CBSE 11-science - Maths
immediately please tell me this question's answer
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Asked by akankhyapradhan123 | 18 Jan, 2022, 06:16: AM
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CBSE 11-science - Maths
Please answer this question.
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Asked by dineshchem108 | 02 May, 2019, 09:00: PM
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CBSE 11-science - Maths
What is the answer for this question?
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Asked by dineshchem108 | 01 May, 2019, 07:09: PM
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CBSE 11-science - Maths
What is the answer for this question?
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Asked by dineshchem108 | 16 Apr, 2019, 10:58: PM
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CBSE 11-science - Maths
if f(x)=open curly brackets 2 x plus 3 space comma x less or equal than 0 3 open parentheses x plus 1 close parentheses comma x greater than 0 close curly brackets space .find lim f(x)  x->1               
Asked by Shivendra | 23 Oct, 2018, 10:18: PM
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CBSE 11-science - Maths
19th one plz
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Asked by lovemaan5500 | 20 Jul, 2018, 06:12: PM
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CBSE 11-science - Maths
20th plz
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Asked by lovemaan5500 | 20 Jul, 2018, 06:12: PM
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CBSE 11-science - Maths
27th plz
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Asked by lovemaan5500 | 19 Jul, 2018, 06:30: PM
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CBSE 11-science - Maths
How to solve simple limit sums as 1 and  2 parts of first sum
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Asked by lovemaan5500 | 17 Jul, 2018, 06:06: PM
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CBSE 11-science - Maths
How to do these questions?
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Asked by smanishkumar2002 | 25 Apr, 2018, 02:25: PM
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