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CBSE Class 11-science Answered

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Asked by dineshchem108 | 02 May, 2019, 09:00: PM
Expert Answer
begin mathsize 16px style limit as straight x rightwards arrow 0 of space fraction numerator integral subscript 0 superscript straight x space tdt over denominator xtan open parentheses straight x plus straight pi close parentheses end fraction
equals limit as straight x rightwards arrow 0 of space fraction numerator open square brackets begin display style straight t squared over 2 end style close square brackets subscript 0 superscript straight x over denominator xtanx end fraction
equals limit as straight x rightwards arrow 0 of space fraction numerator straight x squared over 2 over denominator xtanx end fraction
equals limit as straight x rightwards arrow 0 of space fraction numerator straight x over denominator 2 tanx end fraction
equals 1 half end style
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