what is a probability of having 53 Thursdays in a non leap year
Asked by yogesh | 10th Jan, 2014, 07:04: PM
Expert Answer:
Number of days in a non-leap year = 365 = 53 weeks and 1 day
Thus, the probability is to be calculated for the remaining 1 day.
That one day can be {Sun, Mon, Tues, Wed, Thurd, Fri, Sat}
Total number of outcomes = 7
Number of facourable outcome = 1
Thus, required probability = 1/7
Answered by | 11th Jan, 2014, 12:40: AM
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