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Asked by pritam | 25 Oct, 2009, 12:29: PM
answered-by-expert Expert Answer

Since the stone is at rest, the external force is zero and momentum is conserved.

ΔP = 0

m2v2 - m1v1 = 0

The momentum of the first piece = m1v1 =  (2)(10) = 20 kgm/s in the east direction.

The momentum of the first pice = m2v2 = 20m2 kgm/s in the west direction.

m1v1 = m2v2

m2 = 20/20 = 1 kg.

The velocity of second piece is in the west direction and mass of it is 1 kg.

Regards,

Team,

TopperLearning.

 

Answered by | 26 Oct, 2009, 02:23: PM

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