Two years ago father was 5 times as old as his son two years laters his age will be 8 more than 3 times of the age of his son.find the precent age.

Let the present age of the father be x years and present age of son be y years

Two year ago the age of father = x-2 years

Two year ago the age of son = y-2 year

 

Case I: x-2 = 5(y-2)

x-2 = 5y-10

x-5y = -8

5y-x = 8

5y-8 = x

 

Case II: x+2 =3(y+2) +8

Putting the value of y

5y-8+2=3y+6+8

2y = 20y = 10 years

 

Putting the value of y in equation 1

X = 5(10)-8 = 42years

 

Present age of father =42 years

Son's present age = 10 years