CBSE Class 9 Answered
Two hockey players of
opposite teams, while trying to hit a
hockey ball on the ground collide and
immediately become entangled. One
has a mass of 60 kg and was moving
with a velocity 5.0 m s–1 while the other
has a mass of 55 kg and was moving
faster with a velocity 6.0 m s–1 towards
the first player. In which direction and
with what velocity will they move after
they become entangled? Assume that
the frictional force acting between the
feet of the two players and ground is
negligible.
Asked by sasikumarsarala2020 | 25 Jun, 2021, 16:37: PM
Type of collision is Inelastic , only momentum is conserved .
Total momentum pi before collision, pi = m1 u1 + m2 u2
where m1 and m2 are masses of player-1 and player-2 . Velocity of player-1 before collision is u1 and that of player-2 is u2
pi = ( 60 × 5 ) - ( 55 × 6 ) = -30 kg m/s
Momentum pf after collision = ( m1 + m2 ) v
where v is velocity of entangled players
By momentum conservation , ( m1 + m2 ) v = 115 v = -30
Hence , velocity v = ( -30 / 115 ) = -0.26 m/s
Hence , after collision, entangled players will move with velocity 0.26 m/s in the direction of initial velocity of player-2
Answered by Thiyagarajan K | 25 Jun, 2021, 17:54: PM
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