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CBSE Class 9 Answered

A ball moving at a constant speed 10m/s, hits normally on a wall (mass of ball is 50g) and rebounds with same speed. The change in momentum is

Asked by mohitdhoni706 | 03 Apr, 2020, 01:20: PM
Expert Answer
m= 50 g = 0.05 kg 
initial velocity and final veocity are equal 
vf = vi 
Change in momentum = Δp = final momentum - initial momentum = mvf - mvi = m(vf - vi) = 0
Ths, 
change in momentum of ball will be zero. 
Answered by Shiwani Sawant | 03 Apr, 2020, 02:39: PM
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