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Asked by janjeetyadav1 | 29th Jul, 2021, 08:18: AM

Expert Answer:

Mass of floating object = mass of displaced water = immersed volume × density of water
 
Let ρA is density of solid-A  and VA is its volume. 
 
density ρA = mass / volume = [ (1/4) VA  × ρW ] / VA  = (1/4) ρW
 
where ρW is density of water
 
Let ρB is density of solid-B  and VB is its volume. 
 
density ρB = mass / volume = [ (3/5) VB  × ρW ] / VA  = (3/5) ρW
 
Ratio of densities ,  ρA  :   ρB  = (1/4) ρW  : (3/5) ρW =  5 : 12

Answered by Thiyagarajan K | 29th Jul, 2021, 09:16: AM

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