Asked by janjeetyadav1 | 29th Jul, 2021, 08:18: AM
Mass of floating object = mass of displaced water = immersed volume × density of water
Let ρA is density of solid-A and VA is its volume.
density ρA = mass / volume = [ (1/4) VA × ρW ] / VA = (1/4) ρW
where ρW is density of water
Let ρB is density of solid-B and VB is its volume.
density ρB = mass / volume = [ (3/5) VB × ρW ] / VA = (3/5) ρW
Ratio of densities , ρA : ρB = (1/4) ρW : (3/5) ρW = 5 : 12
Answered by Thiyagarajan K | 29th Jul, 2021, 09:16: AM
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