JEE Class main Answered
trigonometry
![question image](http://images.topperlearning.com/topper/new-ate/top_mob170126327019799508433e418d61-f67e-4b05-85c3-3bf6fe3eef66.jpg)
Asked by anuragrr1222 | 29 Nov, 2023, 18:37: PM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/ca2b04104ff3cf2f97beb9506500c417656813ffe68a04.64807036g1.png)
Above figure shows Δ ABC with
C = 90o
![begin mathsize 14px style angle end style](https://images.topperlearning.com/topper/tinymce/cache/f1d45fc0daa19a85e39a8446cd27e48f.png)
tan(A) = a/b and tan(B) = b/a
c2 = a2 + b2
Let us consider the following equation
(ab) x2 - c2 x + ab = 0
Roots of above equation are
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/83f3ee619d92155fc09a8d5005ec8b61656817c6a043e5.96121485g1.png)
Hence roots are a/b and b/a
Only equation gives the roots as tanA and tanB is " (ab) x2 - c2 x + ab = 0 "
Answered by Thiyagarajan K | 30 Nov, 2023, 10:37: AM
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