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Time- 0 10 20 30 40 50

Speed- 5 10 15 20 25 30

Find the distance travelled in 50 seconds

Asked by akshatdhamija1409 | 15 Jul, 2022, 11:16: PM
speed keep on increasing with respect to time. Hence this is accelerated motion.

acceleration a = Δv / Δt

where Δv is change in speed in a time duration Δt

we see from given data, speed increases by 5 m/s  for every 10 s .

Hence acceleration a = 5/10 = 0.5 m/s2

distance travelled S in time duration t is given as

S = u t + (1/2) a t2

where u is initial speed at t=0

distance travelled in 50 s = 5×50  + (1/2)×0.5 × 502 = 875 m
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Graphical method

Graph of speed Vs. time is shown above . Distance travelled equals area under the graph of speed Vs. time.

In the plotted grpah, distance travelled in 50 s is obtained from the area of trapezium OABC

Area of trapezium OABC = (1/2) × OC × [ OA + BC ] = (1/2) × 50 × [ 5 + 30 ] = 875  m

Hence distance travelled in 50 s = 875 m
Answered by Thiyagarajan K | 16 Jul, 2022, 08:55: AM

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