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CBSE Class 9 Answered

Time- 0 10 20 30 40 50 Speed- 5 10 15 20 25 30 Find the distance travelled in 50 seconds
Asked by akshatdhamija1409 | 15 Jul, 2022, 23:16: PM
answered-by-expert Expert Answer
speed keep on increasing with respect to time. Hence this is accelerated motion.
 
acceleration a = Δv / Δt
 
where Δv is change in speed in a time duration Δt
 
we see from given data, speed increases by 5 m/s  for every 10 s .
 
Hence acceleration a = 5/10 = 0.5 m/s2
 
distance travelled S in time duration t is given as
 
S = u t + (1/2) a t2
 
where u is initial speed at t=0
 
distance travelled in 50 s = 5×50  + (1/2)×0.5 × 502 = 875 m
----------------------------------------------------------------------------------------
 
Graphical method
 
Graph of speed Vs. time is shown above . Distance travelled equals area under the graph of speed Vs. time.
 
In the plotted grpah, distance travelled in 50 s is obtained from the area of trapezium OABC
 
Area of trapezium OABC = (1/2) × OC × [ OA + BC ] = (1/2) × 50 × [ 5 + 30 ] = 875  m
 
Hence distance travelled in 50 s = 875 m
Answered by Thiyagarajan K | 16 Jul, 2022, 08:55: AM

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CBSE 9 - Physics
Time- 0 10 20 30 40 50 Speed- 5 10 15 20 25 30 Find the distance travelled in 50 seconds
Asked by akshatdhamija1409 | 15 Jul, 2022, 23:16: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
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