the value 21/4. 41/8. 81/6..... is

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the value 21/4. 41/8. 81/6..... is

Asked by sabeenashaik575 | 09 Jan, 2024, 09:53: AM

Expert Answer

To find the value of 2^{1/4} x 4^{1/8} x 8^{1/16} x ...

Subtracting S/2 from S, we get

Thus, S = 1

Answered by Renu Varma | 09 Jan, 2024, 10:35: AM

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JEE main - Maths

solv

Asked by vishwajeetsinghrajput2018 | 17 Mar, 2024, 12:27: AM

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solve

Asked by mailtome.aj86 | 26 Feb, 2024, 08:29: PM

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JEE main - Maths

the value 21/4. 41/8. 81/6..... is

Asked by sabeenashaik575 | 09 Jan, 2024, 09:53: AM

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JEE main - Maths

solution

Asked by 20sanjaykoley20 | 19 Dec, 2023, 12:57: AM

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JEE main - Maths

Let S be the sum P the product and R the sum of reciprocal

Asked by kunmunkumar08032008 | 08 Oct, 2023, 01:15: PM

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JEE main - Maths

Let Tr be the rth term of an AP for r=1,2,3,.... If for some positive integers m, n. We have Tm=1/n and Tn=1/m, then Tmn equals to

Asked by nitinsolanki14102001 | 16 Sep, 2023, 03:01: PM

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JEE main - Maths

if an= -2/(4n^2)-(16n)+(15), [(4n^2)-(16n)+(15) dis entire thing is the denominator)] then: opt a) a1+a2+....+a10= 20/51 opt b) a1+a2+.....a10=30/51 opt c) a1+a2+......a25=50/141 opt d) a1+a2+.....a25=60/141 Its more than one ans type q, pls tell me a detailed explanation on how to do it as i din understand

Asked by joanmaria916 | 08 Jul, 2023, 04:37: PM

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JEE main - Maths

There are (4n + 1) terms in a certain sequence of which the first (2n + 1) terms form an A.P. of common difference 2 and the last (2n + 1) terms are in G.P. of common ratio 1/2 If the middle term of both A.P. and G.P. are the same, then find the mid-term of this sequence.

Asked by vishnuramrs07 | 30 May, 2023, 09:05: PM

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JEE main - Maths

The sum of the common terms of the following three arithmetic progressions. 3,7,11,15,…………,3993,7,11,15,…………,399 2,5,8,11,.........3592,5,8,11,.........359 and 2,7,12,17,……,1972,7,12,17,……,197, is equal to _____ .

Asked by chiyalaxmi28 | 18 Mar, 2023, 10:34: AM

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JEE main - Maths

AP the sum of integers from 1 to 100 that are devisible by 2 or 5 is

Asked by thakuranurag0987 | 27 Dec, 2022, 02:31: PM

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