solv - 4zstcmoo

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solv

Asked by vishwajeetsinghrajput2018 | 17 Mar, 2024, 12:27: AM

Expert Answer

Each term in above series is a term in aritmetic progression with first term 8/15 and common difference 4/15

Hence sum of series is

Middle term is sum of 9 terms 1 +2 +3......... 9 ; Third term is sum of 9 terms of squares 1² + 2² + 3²+ ................+9²

S = (16/5) × 101

hence , we get , m = 101

Answered by Thiyagarajan K | 17 Mar, 2024, 09:31: AM

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JEE main - Maths

solv

Asked by vishwajeetsinghrajput2018 | 17 Mar, 2024, 12:27: AM

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JEE main - Maths

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JEE main - Maths

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JEE main - Maths

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JEE main - Maths

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JEE main - Maths

Let Tr be the rth term of an AP for r=1,2,3,.... If for some positive integers m, n. We have Tm=1/n and Tn=1/m, then Tmn equals to

Asked by nitinsolanki14102001 | 16 Sep, 2023, 03:01: PM

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JEE main - Maths

if an= -2/(4n^2)-(16n)+(15), [(4n^2)-(16n)+(15) dis entire thing is the denominator)] then: opt a) a1+a2+....+a10= 20/51 opt b) a1+a2+.....a10=30/51 opt c) a1+a2+......a25=50/141 opt d) a1+a2+.....a25=60/141 Its more than one ans type q, pls tell me a detailed explanation on how to do it as i din understand

Asked by joanmaria916 | 08 Jul, 2023, 04:37: PM

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JEE main - Maths

There are (4n + 1) terms in a certain sequence of which the first (2n + 1) terms form an A.P. of common difference 2 and the last (2n + 1) terms are in G.P. of common ratio 1/2 If the middle term of both A.P. and G.P. are the same, then find the mid-term of this sequence.

Asked by vishnuramrs07 | 30 May, 2023, 09:05: PM

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JEE main - Maths

The sum of the common terms of the following three arithmetic progressions. 3,7,11,15,…………,3993,7,11,15,…………,399 2,5,8,11,.........3592,5,8,11,.........359 and 2,7,12,17,……,1972,7,12,17,……,197, is equal to _____ .

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JEE main - Maths

AP the sum of integers from 1 to 100 that are devisible by 2 or 5 is

Asked by thakuranurag0987 | 27 Dec, 2022, 02:31: PM

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