CBSE Class 11-science Answered
The moment of inertia of a circulating ring passing through its centre and perpendicular to its plane is 400g cm2. If the radius of ring is 5 cm, find the mass of the ring.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Here, 
= 400 g cm2
= 400 g cm2 R= 5 cm
Now, moment of inertia of the ring, = MR2
= MR2Therefore,
Answered by | 04 Jun, 2014, 03:23: PM
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