CBSE Class 11-science Answered
The moment of inertia of a circulating ring passing through its centre and perpendicular to its plane is 400g cm2. If the radius of ring is 5 cm, find the mass of the ring.
Asked by Topperlearning User | 04 Jun, 2014, 13:23: PM
Here,
= 400 g cm2
![](https://images.topperlearning.com/topper/questions/8741_image001.gif)
R= 5 cm
Now, moment of inertia of the ring,
= MR2
![](https://images.topperlearning.com/topper/questions/8741_image001.gif)
Therefore,
![](https://images.topperlearning.com/topper/questions/8741_image002.gif)
Answered by | 04 Jun, 2014, 15:23: PM
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