The moment of inertia of a circulating ring passing through its centre and perpendicular to its plane is 400g cm2. If the radius of ring is 5 cm, find the mass of the ring.

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

Here, = 400 g cm2
          R= 5 cm
Now, moment of inertia of the ring,  = MR2
Therefore,

Answered by  | 4th Jun, 2014, 03:23: PM