The maximum and the minimum values, if any of the following functions f (x) = 3x2 + 6x + 8,

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

We have,

f (x) = 3x2  + 6x + 8
f (x) = 3(x2  + 2x + 1) + 5 = 3(x + 1)2 + 5
Now, for all
  for all
  for all
Thus, 5 is the minimum value of  f (x) which it attains at x = – 1
Since f (x) can be made as large as we please. Therefore, the maximum value does not exist

Answered by  | 4th Jun, 2014, 03:23: PM