the frequency (f) of an oscillating drop depends upon radius (r)of the drop , density(P)of the liquid and the surface tension(t) of the liquid .find the expression of the frquency(k is the dimensional constant). a) F=k*(t/pr^2)^1/3 b)F=k*(t/pr^3)^1/2 c)F=k*(p/tr^3)^1/2 d)None of these find the right answer
Asked by pooja dev | 9th Jun, 2011, 12:00: AM
Expert Answer:
let frequency, ? = k ra pb tc
Putting the dimensions of quantities, we have
[T-1] = 1 [L]a [ML-3]b [MT-2]c
comparing the powers we have
-2c = -1, c = 1/2;
b + c = 0, b = - 1/2;
a - 3b = 0, a = - 3/2;
Therefore, ? = k sqrt (t / P r3)
So, b is correct.
Answered by | 13th Jun, 2011, 02:23: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change