NEET Class neet Answered
The freezing point of an aqueous solution of KCN containing 0.189 mol/kg was -0.704 C .On adding 0.095 mol of Hg(CN)2, the freezing point of the solution bacame -0.53 C .What will be new 'i' factor of the resulting ? [assuming that the Hg(CN)2 and KCN produced the complex].
Asked by Balbir | 30 Jul, 2019, 04:06: PM
Expert Answer
Given:
Molality of KCN solution = 0.1892 mol/kg
We know,
ΔTf = Kf × m × i
Answered by Varsha | 31 Jul, 2019, 03:06: PM
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