the eccentricity of the hyperbola x^2 -4y^2=1 is?
Asked by PRERNA | 12th Nov, 2013, 11:47: PM
Expert Answer:
Equation of the hyperbola: x2 - 4y2 = 1
Comparing with equation 
, we get
a2 = 1 and b2= 1/4
Now, b2= a2(e2-1)
i.e. 
=1(e2-1)
i.e. e2 = 1 + 1/4 = 5/4
Thus, e = 
, we get=1(e2-1)Answered by Rashmi Khot | 13th Nov, 2013, 11:20: AM
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