The diagonal of a rectangle ABCD intersect at O. iff BOC
= 44 find OAB.

Asked by Yash | 5th Nov, 2017, 05:57: PM

Expert Answer:

Parallelogram Properties:
 
begin mathsize 16px style We space have comma
angle BOC plus angle BOA equals 180 degree space space space space space space left parenthesis Linear space Pair right parenthesis
rightwards double arrow 44 degree plus angle BOA equals 180 degree
rightwards double arrow angle BOA equals 136 degree
Since space diagonals space of space straight a space rectangle space are space equal space and space they space bisect space each space other comma
therefore comma space in space triangle OAB comma space we space have
OA equals OB
rightwards double arrow angle OAB equals angle OBA space space space space space space space space left curly bracket Angles space opposite space to space equal space sides space are space equal right square bracket
Now comma space in space triangle OAB comma
angle OAB plus angle OBA space plus angle BOA equals 180 degree
rightwards double arrow 2 angle OAB plus 136 degree equals 180 degree
rightwards double arrow 2 angle OAB equals 44 degree
rightwards double arrow angle OAB equals 22 degree end style

Answered by Rashmi Khot | 4th Dec, 2017, 03:01: PM