Find the measure of each angle of a parallelogram, if one of its angles is 30o less than twice the smallest angle.

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

Let the smallest angle be x.
Then one of the angles is 2x – 30o
(2x – 30o) + x = 180o              
(Interior angles on same side of transversal are supplementary)
 x = 70o   
One angle = (2x – 30o) = 110o
Opposite angles of a parallelogram are equal
Hence, the four angles are 70o, 110o, 70o, 110o

Answered by  | 4th Jun, 2014, 03:23: PM