The base BC of an equilateral triangle ABC lies on y-axis. The coordinates of point C are (0,-3). If the origin is the mid point of the base BC, Find the coordinates of the points A and B.

Asked by Palak Shrivastava | 15th Nov, 2013, 07:16: PM

Expert Answer:

The base BC of an equilateral triangle ABC lies on Y-axis and O is the mid-point.

Thus, OC = OB = 3 units

Thus, coordinates of B are (0, 3)

Since OX is perpendicular to BC and altitude of equilateral triangle passes through the opposite vertex, A lies on –axis.

Now, let the coordinates of AB be (x, 0)

Since AB = BC, we have

Thus, coordinates of A are ( and B are (0, 3)

Answered by Rashmi Khot | 15th Nov, 2013, 08:12: PM

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