CBSE Class 10 Answered
find the point on the y-axis which equidistant from (4,1)and (-3,5)
Asked by jdharmendra097 | 21 Feb, 2024, 20:02: PM
it is required to get a point C(0,y ) on y-axis which is equidistant from A(4,1) and B(-3,5)
Since distance AC is equal to distance BC , then we have
From above expression, we get , y = 17/8 = 2.125
Hence equidistant point from A (4, 1 ) and B (-3, 5 ) is C (0, 2.125)
Answered by Thiyagarajan K | 21 Feb, 2024, 22:36: PM
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