JEE Class main Answered
Sum of all real values of x satisfying the equation (x²–5x+5)^(x²+4x–60) = 1
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Asked by anandprashant2022 | 29 Jul, 2022, 21:44: PM
![open parentheses x squared plus 5 x plus 5 close parentheses to the power of open parentheses x squared minus 4 x plus 60 close parentheses end exponent equals 1 to the power of 0
rightwards double arrow x squared plus 5 x plus 5 equals 1 space space & space space x squared minus 4 x plus 60 equals 0
rightwards double arrow left parenthesis x plus 4 right parenthesis left parenthesis x plus 1 right parenthesis space & space left parenthesis x minus 10 right parenthesis left parenthesis x plus 6 right parenthesis equals 0
rightwards double arrow x equals negative 4 space o r space x equals negative 1 space & space x equals 10 space o r space x equals negative 6](https://images.topperlearning.com/topper/tinymce/cache/5d7f8462fe28ea8e145c7b0f0930d9c4.png)
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