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Roots of equation x^2-4x+4-a^2=0
Asked by astudent774 | 08 Feb, 2023, 04:14: PM
answered-by-expert Expert Answer
Given queadratic equation is x2 - 4x + 4 - a2
straight x equals fraction numerator 4 plus-or-minus square root of 4 squared minus 4 left parenthesis 4 minus straight a squared right parenthesis end root over denominator 2 end fraction equals fraction numerator 4 plus-or-minus square root of 16 minus 16 plus 4 straight a squared end root over denominator 2 end fraction equals fraction numerator 4 plus-or-minus square root of 4 straight a squared end root over denominator 2 end fraction equals fraction numerator 4 plus-or-minus 2 straight a over denominator 2 end fraction equals 2 plus-or-minus straight a Thus comma space the space roots space are space 2 plus straight a space and space 2 minus straight a.
Answered by Renu Varma | 09 Feb, 2023, 11:18: AM
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Roots of equation x^2-4x+4-a^2=0
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