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Roots of equation x^2-4x+4-a^2=0
Asked by astudent774 | 08 Feb, 2023, 16:14: PM
answered-by-expert Expert Answer
Given queadratic equation is x2 - 4x + 4 - a2
straight x equals fraction numerator 4 plus-or-minus square root of 4 squared minus 4 left parenthesis 4 minus straight a squared right parenthesis end root over denominator 2 end fraction equals fraction numerator 4 plus-or-minus square root of 16 minus 16 plus 4 straight a squared end root over denominator 2 end fraction equals fraction numerator 4 plus-or-minus square root of 4 straight a squared end root over denominator 2 end fraction equals fraction numerator 4 plus-or-minus 2 straight a over denominator 2 end fraction equals 2 plus-or-minus straight a Thus comma space the space roots space are space 2 plus straight a space and space 2 minus straight a.
Answered by Renu Varma | 09 Feb, 2023, 11:18: AM
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JEE main - Maths
if alpha beta are the roots of x square +2x + 5 is equals to zero the equation whose roots are Alpha square + alpha + 1 beta square + beta + 1 is
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JEE main - Maths
1+3/1!(1/3)+x = (1-2/3)^-3/2
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Asked by tarunkumarpalleti | 06 Oct, 2023, 04:27: AM
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JEE main - Maths
Roots of equation x^2-4x+4-a^2=0
Asked by astudent774 | 08 Feb, 2023, 16:14: PM
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JEE main - Maths
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Asked by snehakumar6321 | 14 Jan, 2023, 22:37: PM
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JEE main - Maths
Sum of all real values of x satisfying the equation (x²–5x+5)^(x²+4x–60) = 1
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Asked by anandprashant2022 | 29 Jul, 2022, 21:44: PM
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JEE main - Maths
(2x-3)^2 - |2x-3| -2 =0
Asked by mehraakshita419 | 23 Jul, 2022, 08:44: AM
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