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1+3/1!(1/3)+x = (1-2/3)^-3/2
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Asked by tarunkumarpalleti | 06 Oct, 2023, 04:27: AM
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TO solve the equation: 1 + 3/1! (1/3) + x = (1 - 2/3)^-3/2
Solution:
Answered by Renu Varma | 06 Oct, 2023, 10:34: AM
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JEE main - Maths
if alpha beta are the roots of x square +2x + 5 is equals to zero the equation whose roots are Alpha square + alpha + 1 beta square + beta + 1 is
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JEE main - Maths
letx^2-(m-3)x+m=0 ,m belongs to R . It is a quadratic equation then find th value of m for which at least one root is greater than 2.
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for the equation /X/
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Asked by padmapadmavati952 | 19 Jun, 2024, 20:52: PM
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For a real number r, the quadratics x² + (r-1) x + 6 and x² + (2r + 1) x + 22 have a common real root. the sum of the possible values of r can be expressed as a where a/b where a,b are relatively prime positive integers. compute 10a + b ?
Asked by nomanmalik8850 | 06 May, 2024, 19:33: PM
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JEE main - Maths
1+3/1!(1/3)+x = (1-2/3)^-3/2
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Asked by tarunkumarpalleti | 06 Oct, 2023, 04:27: AM
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JEE main - Maths
Roots of equation x^2-4x+4-a^2=0
Asked by astudent774 | 08 Feb, 2023, 16:14: PM
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JEE main - Maths
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Asked by snehakumar6321 | 14 Jan, 2023, 22:37: PM
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JEE main - Maths
If the difference between roots of the equation x2+ax+3=0 is less than ?3 then sum of all the integral of x is equal to
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JEE main - Maths
Sum of all real values of x satisfying the equation (x²–5x+5)^(x²+4x–60) = 1
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Asked by anandprashant2022 | 29 Jul, 2022, 21:44: PM
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JEE main - Maths
(2x-3)^2 - |2x-3| -2 =0
Asked by mehraakshita419 | 23 Jul, 2022, 08:44: AM
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