# subba rao started work in1995 at annual salary of ₹5000 and received an increment of ₹200 each year .in which year did his income reach ₹7000

### Asked by lavanyamahadhasyam | 16th Dec, 2019, 05:18: PM

Expert Answer:

### According to the condition,
5000, 5200, 5400 .... , 7000 forms an A.P since the difference between the consecutive terms is 200.
Here, a = 5000 , d = 200 and a_{n} = 7000
a_{n} = a + (n - 1)d
→ 7000 = 5000 + (n - 1)200
→ 2000 = 200(n - 1)
→ n - 1 = 10
→ n = 11

In 2005 his income will reach Rs. 7000.

_{n}= 7000

_{n}= a + (n - 1)d

### Answered by Yasmeen Khan | 16th Dec, 2019, 06:20: PM

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