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CBSE Class 10 Answered

subba rao started work in1995 at annual salary of ?5000 and received an increment of ?200 each year .in which year did his income reach ?7000
Asked by lavanyamahadhasyam | 16 Dec, 2019, 17:18: PM
answered-by-expert Expert Answer
According to the condition, 
 
5000, 5200, 5400 .... , 7000 forms an A.P since the difference between the consecutive terms is 200.
 
Here, a = 5000 , d = 200 and an = 7000
 
an = a + (n - 1)d
→ 7000 = 5000 + (n - 1)200
→ 2000 = 200(n - 1)
→ n - 1 = 10
→ n = 11

In 2005 his income will reach Rs. 7000. 
Answered by Yasmeen Khan | 16 Dec, 2019, 18:20: PM

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